Question

Assume 5ft/s of Hydrogen at 15 psia and 80F are compressed during an irreversible adiabatic process to 90 psia and 522F. For a non flow process determine a)k b)V c) W d)U and e)s

Answer 1

$T_2 = 522°F = 545.5K \\ T_1 = 80°F= 300K$

$P_1= 15psia\\ P_2 =90psia$

∆T = 522F -80F = 442F = 228K

∆P = 90psia - 15psia = 75psia

speed rate = 5ft/s

$\dfrac{V_1}{V_2} = \dfrac{P_2×T_1}{P_1×T_2} = \dfrac{90 × 300}{15× 545.5} = 3.3$

Therefore the final volume is 3.3 times lesser than the initial volume.