Assume 5ft/s of Hydrogen at 15 psia and 80F are compressed during an irreversible adiabatic process to 90 psia and 522F. For a non flow process determine a)k b)V c) W d)U and e)s
"T_2 = 522\u00b0F = 545.5K\n\\\\ T_1 = 80\u00b0F= 300K"
"P_1= 15psia\\\\\nP_2 =90psia"
∆T = 522F -80F = 442F = 228K
∆P = 90psia - 15psia = 75psia
speed rate = 5ft/s
"\\dfrac{V_1}{V_2} = \\dfrac{P_2\u00d7T_1}{P_1\u00d7T_2} = \\dfrac{90 \u00d7 300}{15\u00d7 545.5} = 3.3"
Therefore the final volume is 3.3 times lesser than the initial volume.
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