Question #172628

A 0.0856 m3 drums contains saturated water and saturated vapor at 370oC. (a) Find the mass of each if their volumes are equal. What is the quality? (b) Find the volume occupied by each if their masses are equal.


1
Expert's answer
2021-04-01T01:06:01-0400

Density of water at 100°C (as water cannot be hotter than 100°C) is 958 kg/m3.

Pressure of saturated vapor at 370°C is


pws=exp(77.3450+0.0057T7235/T)T8.2=18,575,161 Pa.p_{ws}=\frac{\exp(77.3450 + 0.0057 T - 7235 / T)}{T^{8.2}}=18,575,161\text{ Pa}.

Density of vapor:


ρws=0.0022pwsT=63.5 kg/m3.\rho_{ws}=\frac{0.0022p_{ws}}{T}=63.5\text{ kg/m}^3.

(a) The volume of water or steam is  0.0428 m3. The mass of each volume is


mw=Vρw=0.0428958=41.0 kg,mws=Vρws=2.72 kg.m_w=V\rho_w=0.0428·958=41.0\text{ kg},\\ m_{ws}=V\rho_{ws}=2.72\text{ kg}.

(b) To find volumes, use the equations above:


Vw=mρw, Vws=mρws, V=Vw+Vws=m(1ρws+1ρw), m=Vρwρwsρw+ρws=5.10 kg.V_w=\frac{m}{\rho_w},\\\space\\ V_{ws}=\frac{m}{\rho_{ws}},\\\space\\ V=V_w+V_{ws}=m\bigg(\frac{1}{\rho_{ws}}+\frac{1}{\rho_w}\bigg),\\\space\\ m=V\frac{\rho_w\rho_{ws}}{\rho_w+\rho_{ws}}=5.10\text{ kg}.

The volumes:


Vw=5.10958=5.32103 m3, Vws=5.1063.5=0.0803 m3.V_w=\frac{5.10}{958}=5.32·10^{-3}\text{ m}^3,\\\space\\ V_{ws}=\frac{5.10}{63.5}=0.0803\text{ m}^3.

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