Question #160318

A bus makes a trip according to the position–time graph shown in the drawing. What is the average velocity (magnitude and direction) of the bus during each of the segments labeled A, B, and C? Express your answers in km/h.


Expert's answer

a)

10401.5\frac{ 10-40}{1.5 } = 301.5\frac{30}{1.5} = 20 km/h (retardation)

b) 20102.51.5\frac{20-10}{2.5-1.5} = 101\frac{10}{1} = 10 km/hr (acceleration)

c) 402032.5\frac{40-20}{3-2.5} = 200.5\frac{20}{0.5} = 40 km/h ( acceleration )


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS