Given v=200m/s
From the figure above, the horizontal distance, X=Rcos20=0.94R
Vertical distance, Y=Rsin20=0.342R
Then, X=vcos60×t⟹t=200cos600.94R=0.0094R
Y direction
Y=vy0t−0.5gt2
0.342R=vsin60×t−0.5t2
0.342R=200sin60×0.0094R−0.5×9.81×0.00942
R=2967.2m
Comments
Leave a comment