Answer to Question #156515 in Mechanical Engineering for Rodel

Question

A 60 kg_m body has a potential energy of 135 Kcal with respect to a datum plane X and a potentiaal energy of -99 Kcal with respect to datum plane Y. If the local acceleration of gravity is standard, compute the relative position of plane X relative to plane Y. Resolve the problem if g = fps².

Answer 1

m = 60 kg

E₁ = 135 Kcal = 564 840 J

E₂ = -99 Kcal = -414 216 J

E = mgh

60 kg x 9.8 m/s² x h₁ = 564 840 J

h₁ = 961 m

60 kg x 9.8 m/s² x h₂ = -414 216 J

h₂ = -704 m

Relative position = 961 - 704 = 257