Question #156305

The food compartment of a refrigerator, is maintained at 4°C by

removing heat from it at a rate of 360 kJ/min. If the required power input

to the refrigerator is 2 kW, determine (a) the coefficient of performance of

the refrigerator and (b) the rate of heat rejection to the room that houses

the refrigerator.


Expert's answer

(a) the coefficient of performance of the refrigerator


COP=PCP=360×1000J60s2000W=3{\rm COP}=\frac{P_C}{P}=\rm\frac{360\times \frac{1000\: J}{60\: s}}{2000\: W}=3

(b) the rate of heat rejection to the room that houses the refrigerator

PH=PC+P=360×1000J60s+2000W=8000  WP_H=P_C+P=\rm 360\times \frac{1000\: J}{60\: s}+2000\: W=8000\; W

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