Question

A bowling ball has a mass of 6 kg, a moment of inertia of 1,6 10^-2 kg.m², and a radius of 0,2 m. If it rolls down the lane without slipping at a linear speed 8 m/s, what is its total energy?

Answer 1

The total energy consists of kinetic energy of rotation and kinetic energy of linear motion:

$$E=\frac12 J\omega^2+\frac12 mv^2,\\\space\\ E=\frac12(1.6\cdot10^{-2})(8/0.2)^2+\frac126\cdot8^2=204.8\text{ J}.$$