Question #154897

QUESTION 3

a. A certain engine develops a torque of 120 Nm while running at a speed of 3000 rev/min. Calculate the brake power. Take pie =3,142. (5)

b. An indicator diagram taken from a single-cylinder 4-stroke engine has an effective area of 600 mm2

If the base length of the indicator diagram is 60 mm and the constant is 80 kPa/mm calculate the indicated mean effective pressure


1
Expert's answer
2021-01-18T01:14:25-0500

power =τ×W\tau \times W

=τ×2πN60= \tau\times \frac{2\pi N}{60}

=120×2×3.142×300060= 120\times \frac{2\times3.142\times 3000}{60}

= 37704 watt

= 37.704 KW


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