Answer to Question #153224 in Mechanical Engineering for Amrish

Question #153224

Determine the smallest size of hole that can be punched in 12 mm thick MS 

plate having ultimate shear stress of 390 N/mm2 , if permissible crushing 

stress for the punch material is 2.4 kN/mm2.


1
Expert's answer
2021-01-06T06:04:12-0500

Ultimate shear stress="\\tau_u=" 390 N/mm2, thickness= 12mm,


Permissible crushing stress=2.4 kN/mm2


Axial shear force= "(\\frac{\\pi d^2}{4})\\tau= F" ,In case of crushing


"F=\\pi dt \\times \\sigma_c" as we know that in case of small size both force will be same


"\\pi dt \\sigma_c=\\frac{\\pi d^2}{4}\\times \\tau_u"


12 "\\times 2400= \\frac{d}{4}\\times 390"


d=295.38 mm


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