Answer to Question #152180 in Mechanical Engineering for erikha

Question #152180
A 500 cubic feet per minute of air enters a system whose density is 0.075 lbm/ft3 and discharges it with a density of 0.34 lbm/ft3. The pressure at the suction is 10 psia and at the discharge is 80 psia. The increase in the specific internal energy is 35.8 BTU/lbm. Determine the work in Hp.
1
Expert's answer
2020-12-22T05:07:52-0500

"m = \\rho V"

"m= 0.075 \\times 500 = 37.5" lb/min

According to the balancing work equation

"w= \\frac{-2384.378}{42.4}"

= 56.235 hp



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Assignment Expert
23.12.20, 11:39

Dear erikha, Questions in this section are answered for free. We can't fulfill them all and there is no guarantee of answering certain question but we are doing our best. And if answer is published it means it was attentively checked by experts. You can try it yourself by publishing your question. Although if you have serious assignment that requires large amount of work and hence cannot be done for free you can submit it as assignment and our experts will surely assist you.

erikha
19.12.20, 09:25

A pump delivers 50 kg/s of water from 100 kPa to 300 kPa. The inlet and discharge piping are on the same level, but the diameter of the inlet piping is 16 cm, whereas that of the discharge piping is 11 cm. Determine the work done in kW.

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