Answer to Question #152152 in Mechanical Engineering for Ankit Kumar

Question

find the enthalpy of entropy of steam when the pressure is 20 Bar and specific volume is 0.8

Answer 1

The Dryness fraction(x) of the wet steam=0.8

The pressure of wet steam(P)=20 bar=2 MPa J/kg

The saturation properties of wet steam at 2 MPa is given

in the steam table as

$V= 0.0012 m3/kg Vtg (0.0996-0.0012)=0.0984 m3/kg$

$h=908.5 kJ/kg hig=1889.8kJ/kg$

$U = 906.15 kJ/kg Ufq= (2599.1-906.15) =1692.95 kJ/Kg S= 2.4468 kJ/kg-K s=3.8923 KJ/kg-K$

Specific volume at $x=0.8 = v=vf+x.vfg=0.07992 m3/kg$

Specific enthalpy at $x=0.8 => h=hf+x.hfg=2420.34 kJ/kg$

Specific internal energy at $x=0.8=>u=uf+x.ufg=2260.51 k$

Specific entropy at $x=0.8 => s=sf+x sfg=5 5606 kJ/kg-K$