Question #107512
The pressure difference p of air that flows through a fan is a function of the diameter D of the blade, its angular rotation, density of the air, and the flow Q. Use the FLT method of repeating variables to generate a dimensionless relationship between these parameters
1
Expert's answer
2020-04-02T09:30:03-0400

In FLT method of dimension we take F(Force), L(Length) and T (Time ) as standard dimension and find the dimension of other quantities in terms of FLT

Here pressure difference is function of diameter of blade(D), Angular rotation(θ\theta), density of air (ρ\rho ) and the flow (Q).


Δp=k(D)a(θ)b(ρ)c(Q)d\Delta p=k (D)^a(\theta)^b(\rho)^c(Q)^d


Now here equate the dimension of the above quantities in terms of FLT


Δp=FL2,D=L,ρ=FL4T2,Q=L3T1\Delta p=FL^{-2},D= L,\rho=FL^{-4}T^2,Q=L^3T^{-1}


now equate the dimension of all the quantities in above equation


(FL2)=k(L)a(F0L0T0)b(FL4T2)c(L3T1)d(FL^{-2})=k (L)^a(F^0L^0T^0)^b(FL^{-4}T^2)^c(L^3T^{-1})^d


On comparing with the dimensions of the above quantities we can say that


F1L2T0=La4c+3dFcT2cdF^1L^{-2}T^0= L^{a-4c+3d} F^{c}T^{2c-d}

on comparing the power of dimension we can say that,

c=1,

2 c-d=0

2 c=d

d=2,

a-4c+3d=-2

1-4+6=-2

a=-5


so from here we can say that the relation is as follows


Δp=\Delta p= kD5ρQ2D^{-5}\rho Q^2


Δp=k(ρQ2D5)\Delta p=k (\frac{\rho Q^2}{D^5})



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