Here in question it is given the enthalpy of air as ha=320 KJ/kg and the enthalpy of fuel is
hf=43027 kJ/kg the gases leaving at an enthalpy of hm=616 Kj/kg here , for heating air the fuel requirement is "17 \\frac{kg(air)}{kg(fuel)}" so,
Here it is given that hose required heat as 17.02 kW = "17.02 \\frac{kJ}{s}"
Total heat requirement per day by hose will = "17.02\\times3600\\times24=1470528 kJ"
Net enthalpy exchange by air to heat the hose = "(h_f+h_a)-h_m=42731 kJ" /kg
so, net mass of air consumption per day "= \\frac{1470528}{42731} =34.41 Kg" /day
so net mass of fuel consumption per day ="\\frac{34.41}{17.02}=2.02 kg" of fuel per day
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