Question

A 3Ω,6Ω,9Ω and 12Ω resistor are connected in series. What resistor that will consume the most
power?

Answer 1

First, we determine what's the equivalent resistance of the 3Ω and 6Ω resistors

Using the quick method, it's

(3×6)÷(3+6) or 2Ω

So the circuit's effectively 3Ω in series with 2Ω, 5Ω in total.

Current according to Ohm's Law is

I=V/R

V = 5V, R = 5Ω so I = 1A So, Ohm's Law again to calculate the voltage drop across the 3//2

combination,

V = IR, I is 1, R is 2, so the answer's 2V.