Question #243401

Three resistors Ra,Rb,& Rc are connected in series to a 120volt source, and the total power taken by the
circuit is 200 watts. Rb = 2Ra, Rc =3Ra. If Ra,Ra,& Rc are connected in parallel, the equivalent resistance
will be?

Expert's answer

The power disipated in circuit

P1=V2Rnet1=V2Ra+Rb+Rc=V26RaP_1=\frac{V^2}{R_{\rm net 1}}=\frac{V^2}{R_{a}+R_b+R_c}=\frac{V^2}{6R_{a}}

Hence

Ra=V26P1=12026200=12ΩR_a=\frac{V^2}{6P_1}=\frac{120^2}{6*200}=12\:\Omega

The equivalent resictance for the parallel circuit

R=11Ra+1Rb+1RcR=\frac{1}{\frac{1}{R_a}+\frac{1}{R_b}+\frac{1}{R_c}}

R=1112+1212+1312=6.5ΩR=\frac{1}{\frac{1}{12}+\frac{1}{2*12}+\frac{1}{3*12}}=6.5\:\Omega


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