The power disipated in circuit
"P_1=\\frac{V^2}{R_{\\rm net 1}}=\\frac{V^2}{R_{a}+R_b+R_c}=\\frac{V^2}{6R_{a}}"Hence
"R_a=\\frac{V^2}{6P_1}=\\frac{120^2}{6*200}=12\\:\\Omega"The equivalent resictance for the parallel circuit
"R=\\frac{1}{\\frac{1}{R_a}+\\frac{1}{R_b}+\\frac{1}{R_c}}""R=\\frac{1}{\\frac{1}{12}+\\frac{1}{2*12}+\\frac{1}{3*12}}=6.5\\:\\Omega"
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