Three resistors Ra,Rb,& Rc are connected in series to a 120volt source, and the total power taken by the
circuit is 200 watts. Rb = 2Ra, Rc =3Ra. If Ra,Ra,& Rc are connected in parallel, the equivalent resistance
will be?
The power disipated in circuit
P1=Rnet1V2=Ra+Rb+RcV2=6RaV2Hence
Ra=6P1V2=6∗2001202=12ΩThe equivalent resictance for the parallel circuit
R=Ra1+Rb1+Rc11
R=121+2∗121+3∗1211=6.5Ω