Question #243205

Three resistors of 10, 12 and "x" ohms, respectively are connected in parallel across a constant current source of 8A. Determine "x" if this resistor draws 2.5 A.


Expert's answer

110+112+1x=12.5x8x=12Ω\frac{1}{10}+\frac{1}{12}+\frac{1}{x}=\frac{1}{2.5\cdot x}8\\x=12\Omega


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