Answer to Question #319691 in Civil and Environmental Engineering for Chaddwick

Question

Determine the uncorrected and corrected weights based on the following data:

A.Fine Aggregates - Natural

Fineness Modulus = 2.80

Specific Gravity (SSD) = 2.50

Moisture Content,% = 0.50

Absorption, % = 1.80

B.Coarse Aggregates - Angular

Maximum size,mm = 19.00

Spec.Gravity(SSD) = 2.65

Moisture Content,% = 1.35

Absorption,% = 0.80

C.Class of Concrete = Structural

D.Cement Factor = 11.10 bags/cu.m.

E.Slump,mm = 76.20

F.Spec. Gravity of Cement = 3.15

G.Flexural Strength,Mpa = 27.50

Answer 1

corrected weight = aggregate weight $\times$ 105%

= 0.50 $\times$ 104.45%

= 52.225

uncorrected weight => $Wc = Wo\times(\sqrt1+ (\frac{s}{100})^2)$

$Wc = 76.20\times(\sqrt1+ (\frac{19}{100})^2)$

= 78.95