Answer to Question #191072 in Civil and Environmental Engineering for Joshua

Question #191072

Given a normal distribution with mean equal to 40 and a standard deviation of 6, find the value of x that has 14% of the area to the right.


1
Expert's answer
2021-05-26T16:28:02-0400

p(x>k=0.14p(x>k=0.14

i.e p(x<k)=0.86p(x<k)=0.86

So K correspond to P86

{usng excel}

== NORMSINV (0.86)=1.0803(0.86)=1.0803

Hence Z =1.0803=1.0803

(K40)16=1.0803(K-40)16=1.0803

K=40+1.0803×6K=40+1.0803\times 6

K=46.4819K=46.4819

P86=46.4819P86=46.4819

K=46.48K=46.48

So, the value of x=46.48x=46.48 that has 1414% of the area to the right


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