a water tank in the shape of a right circular cone has an altitude of 15 feet and a base radius of 10 feet. If the tank is full of water, find the work done in pumping all the water over the top of the tank.
For the purpose of SI units, I convert the foot to meter first
Altitude=15 feet=4.571meter
Radius at top=10feet=3.04m
Pouring out water is required from 0 to height of 4.571 full height of tank. It requires integration to be done on the given limit
Work = Force x distance
Force=weight density x volume
Force=9.81x density x volume
Force=9.81x1000xvolume
Force=9.81*1000*3.14* x^2*dy
Work=9.81*1000*3.14* x^2*dy(15-y)
Work=9.81*1000*3.14* x^2* (15-y)dy
Slope=m=15/10=1.5
y-0+m(x-0)
y=1.5x
x=y/1.5
x=2/3y=
Thus work is
Work=9.81*1000*3.14* (0.66^2)* (15-y)dy
Work=13690.4(15-y)dy
Work=13690.4(15y-y^2)
Work=13690.4(15*4.571-(4.571)^2))
Work=652634.49Nm
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