Question

Calculate the energy stored for the series-parallel combination shown in figure 3 if C1 = 2 µF, C2 = 3 µF, C3 = 4 µF, C4 = 6 µF, and C5 = 8 µF and the charge to a potential difference of 2600 V.

Answer 1

$C_P = C_1+ C_2+C_3+C_4+C_5$ parallel arrangement

$C_p = 2+ 3+4+6+8 = 25\mu F$

Energy stored E = $\frac{CV^2}{2}$

E= $\frac{25\times 10^{-6} \times 2600^2}{2} = 84.5 J$

Charge stored for the whole system Q= CV

$Q= 25 \times 10^{-6} \times 2600= 0.065 Coulumbs$