The probability that a certain product is defective is 0.35. Find the probability that exactly 3 of the next 5 products taken is non-defective.
Binomial distribution is used
Probability of r defective from n products
p(r)=nCr(p)^(r)q^(n-r)
Probability of exactly 3 defective from 5 products
p(3)=5C3(0.35)^(3)q^(5-3)
p(3)=10(0.35)^(3)(1-0.35)^(5-3)
p(3)=10(0.35)^(3)(0.65)^(2)
p(3)=10(0.35)^(3)(0.65)^(2)
p(3)=0.1811
Thus probability of exactly 3 not defective is 1-0.1811=0.81
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