Determine the hydrostatic force on a triangular plate that is submerged in water.
6m wide and 4m high.
hydrostatic force = pressure ×Area\times Area×Area
pressure = ρgdy\rho gdyρgdy
= 1000×9.8×dy1000 \times 9.8 \times dy1000×9.8×dy
from similar triangles
6w=4y\frac{6}{w}= \frac{4}{y}w6=y4
w=32yw= \frac{3}{2}yw=23y
force therefore = 1000×9.8×(4−y)(32)dy1000\times 9.8\times (4-y)(\frac{3}{2})dy1000×9.8×(4−y)(23)dy
= ∫049800×(4−y)(32)dy\int_0^4 9800\times (4-y)(\frac{3}{2})dy∫049800×(4−y)(23)dy
hydrostatic force = 156800N156800 N156800N
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