Find the volume of the tetrahedron boulded by the coordinate planes and theplane x/a+y/b+z/c=1
The volume bounded by coordinates plane and the plan x/a+y/b+z/c =1 is abc/6 cubic.units.
To find: the volume bounded by coordinates plane and the plan x/a+y/b+z/c =1
Given,
The equations of the lines situated on the planes y=0 and z=0 are:
y=0 gives,
x/a+z/c = 1 ⇔ z = (1−x/a)c,
And,
z=0 gives,
x/a+y/c=1 ⇔ y=(1−x/a)b.
Area A(x) is given by,
A(x) = 1/2(1−x/a)b(1−x/a)c
= bc/2(1−x/a)^2.
Hence the volume is given by the integration of the area A(x) from x = 0 to x = a
V = bc/2(a − 2/a × a^2/2 + 1/a^2 × a^3/3)
V = abc/6.
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