Solve (2y^{3}xe^{y}+y^{2}+y)dx+(y^{3}x^{2}y^{y}-xy-2x)dy=0
(2y3xey+y2+y)dx+(y3x2yy−xy−2x)dy=0dydx=−(2y3xey+y2+y)(y3x2yy−xy−2x)(2y^{3}xe^{y}+y^{2}+y)dx+(y^{3}x^{2}y^{y}-xy-2x)dy=0\\ \frac{dy}{dx}=-\frac{(2y^{3}xe^{y}+y^{2}+y)}{(y^{3}x^{2}y^{y}-xy-2x)}\\(2y3xey+y2+y)dx+(y3x2yy−xy−2x)dy=0dxdy=−(y3x2yy−xy−2x)(2y3xey+y2+y)
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