Question #223876

Solve (2y^{3}xe^{y}+y^{2}+y)dx+(y^{3}x^{2}y^{y}-xy-2x)dy=0


1
Expert's answer
2021-08-30T01:54:05-0400

(2y3xey+y2+y)dx+(y3x2yyxy2x)dy=0dydx=(2y3xey+y2+y)(y3x2yyxy2x)(2y^{3}xe^{y}+y^{2}+y)dx+(y^{3}x^{2}y^{y}-xy-2x)dy=0\\ \frac{dy}{dx}=-\frac{(2y^{3}xe^{y}+y^{2}+y)}{(y^{3}x^{2}y^{y}-xy-2x)}\\


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