Question #223829

The singular integral of z=xp+yq-logpq


1
Expert's answer
2021-08-16T02:19:48-0400

The complete integral of partial differential equation z=xp+yqlogpqz=xp+yq- logpq

Let F=px+qy+p2+q2=0F=px+qy+p^2+q^2=0 . Then by Charpit's auxiliary equations

dpFx+pFz=dqFy+qFz=dzpFpqFq=dxFp=dyFqdpFx+pFz=dqFy+qFz=dz−pFp−qFq=dx−Fp=dy−Fq

we have

dp0=dq0=dzp(x+2p)q(y+2q)=dx(x+2p)=dy(y+2q).dp0=dq0=dz−p(x+2p)−q(y+2q)=dx−(x+2p)=dy−(y+2q) .

This implies p=a=constantp=a=constant . Putting this in given equation, q=y±y24(a2+axz)q=−y±y2−4(a2+ax−z)


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