Given:
F(x,y,z)=xy2+2yz−8,M(3,−2,1)F(x,y,z)=xy^2+2yz-8,\quad M(3,-2,1)F(x,y,z)=xy2+2yz−8,M(3,−2,1)
The unit normal vector to the surface F(x,y,z)=0F(x,y,z)=0F(x,y,z)=0 is given by
Finally
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