Answer to Question #63150 in Chemistry for Glenn
7) NaI + Br2 à NaBr + I2Mass of NaI: 10.0g
Experimental Mass of Br2: 4.52gExperimental Yield of NaBr:6.14g Experiment Yield of I2: 6.93g
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2016-11-08T14:56:08-0500
8) Molar mass of NaI is 149.9 g/mol
Molar mass of Br2 is 159.8 g/mol
Molar mass of NaBr is 102.89 g/mol
Molar mass of I2 is 253.82 g/mol
n = m/M
n(NaI)=10.0/149.9=0.07 mol
n (Br2) = 4.52/159.8 = 0.03 mol
n (NaBr) = 6.14/102.89 = 0.06 mol
n (I2) = 6.93/253.82 = 0.03 mol
According to this, let’s put coefficients to the equation:
2NaI + Br2 2NaBr + I2
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