Answer to Question #63134 in Chemistry for Phillip Jacolow

Question

6) AgNO3 + K3PO4  Ag3PO4+ KNO3 Mass of AgNO3: 25.0g
Experimental Mass of K3PO4: 9.53g Experimental Yield of Ag3PO4: 18.62g Experiment Yield of KNO3: 13.24g

Answer 1

Molar mass of AgNO3: 169,872 g/mol
Molar mass of K3PO4: 212.264 g/mol
Molar mass of Ag3PO4: 418.574 g/mol
Molar mass of KNO3: 101.102 g/mol.
n = m/M
n (AgNO3) = 0.147 mol
n (K3PO4) = 0.045 mol
n (Ag3PO4) = 0.044 mol
n (KNO3) = 0.131 mol
Let’s put coefficients according to these findings to the equation:
3AgNO3 + K3PO4 <-> Ag3PO4+ 3KNO3