Question #62996

How many moles of isooctane must be burned to produce 100 kJ of heat under standard state conditions? Show all your work.

Expert's answer

Question #62996, Chemistry / Other

How many moles of isooctane must be burned to produce 100 kJ of heat under standard state conditions? Show all your work.

Solution:

Standard enthalpy of combustion is 5460.0 kJ mol1-5460.0\ \mathrm{kJ\ mol^{-1}}

2C8H18+25O216CO2+18H2O+5460.0 kJ2C_8H_{18} + 25O_2 \rightarrow 16CO_2 + 18H_2O + 5460.0\ \mathrm{kJ}n=100 kJ×2 mol5460 kJ=0.037 moln = \frac{100\ \mathrm{kJ} \times 2\ \mathrm{mol}}{5460\ \mathrm{kJ}} = 0.037\ \mathrm{mol}

Answer:

0.037 mol

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