Question #62996, Chemistry / Other
How many moles of isooctane must be burned to produce 100 kJ of heat under standard state conditions? Show all your work.
Solution:
Standard enthalpy of combustion is −5460.0 kJ mol−1
2C8H18+25O2→16CO2+18H2O+5460.0 kJn=5460 kJ100 kJ×2 mol=0.037 molAnswer:
0.037 mol
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