Question

The Keq for the equilibrium below is 7.52*10^-2 at 480.0 C.
2Cl2 (g) + 2 H2O (g) <--> 4HCl (g) + O2 (g)

What is the value of Keq at this temperature for the following reaction?
2HCL (g) + 1/2 O2 (g) <--> Cl2 (g) + H2O (g)


A) 5.66 * 10 ^-3
B) 13.3
C) -0.0376
D) 0.274
E) 3.65

Answer 1

Answer on Question #62740 - Chemistry - Other

Task:

The Keq for the equilibrium below is $7.52 \times 10^{-2}$ at $480.0^{\circ} \mathrm{C}$.

$$2 \mathrm{Cl}_2(\mathrm{g}) + 2 \mathrm{H}_2\mathrm{O}(\mathrm{g}) \rightleftharpoons 4 \mathrm{HCl}(\mathrm{g}) + \mathrm{O}_2(\mathrm{g})$$

What is the value of Keq at this temperature for the following reaction?

$$2 \mathrm{HCl}(\mathrm{g}) + \frac{1}{2} \mathrm{O}_2(\mathrm{g}) \rightleftharpoons \mathrm{Cl}_2(\mathrm{g}) + \mathrm{H}_2\mathrm{O}(\mathrm{g})$$

A) $5.66 \times 10^{-5}$

B) 13.3

C) -0.0376

D) 0.274

E) 3.65

Solution:

The reaction (1):

$$2 \mathrm{Cl}_2(\mathrm{g}) + 2 \mathrm{H}_2\mathrm{O}(\mathrm{g}) \rightleftharpoons 4 \mathrm{HCl}(\mathrm{g}) + \mathrm{O}_2(\mathrm{g})$$ $$K_1 = \frac{p_{\mathrm{O}_2}^1 \times p_{\mathrm{HCl}}^4}{p_{\mathrm{Cl}_2}^2 \times p_{\mathrm{H}_2\mathrm{O}}^2};$$

The reaction (2):

$$2 \mathrm{HCl}(\mathrm{g}) + 0.5 \mathrm{O}_2(\mathrm{g}) \rightleftharpoons \mathrm{Cl}_2(\mathrm{g}) + \mathrm{H}_2\mathrm{O}(\mathrm{g})$$ $$K_2 = \frac{p_{\mathrm{Cl}_2} \times p_{\mathrm{H}_2\mathrm{O}}}{p_{\mathrm{O}_2}^{0.5} \times p_{\mathrm{HCl}}^2};$$ $$K_2 = \left(\sqrt{K_1}\right)^{-1} = \frac{1}{\sqrt{K_1}};$$ $$K_2 = \frac{1}{\sqrt{K_1}} = \frac{1}{\sqrt{7.52 \times 10^{-2}}} = \frac{1}{0.274223} = 3.6466;$$ $$K_2 = 3.6466 \approx 3.65;$$

Answer: E) 3.65

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