Question

When heated KCIO3 decomposes into KCI and O2.
2KCIO3-------2KCI+3O2
If this reaction produced 34.6 g of KCI, how much O2 was produced in grams?

Answer 1

Question #62559, Chemistry / Other

When heated KClO3 decomposes into KCl and O2.

2KClO3---2KCl+3O2

If this reaction produced 34.6 g of KCl, how much O2 was produced in grams?

Answer:

The number of moles of KCl equals:

$$v(KCl) = m(KCl)/Mr(KCl) = 34.6 \ \text{g}/74.55 \ \text{g mol}^{-1} = 0.4641 \ \text{mol}$$

According to the reaction 2 moles of KClO₃ produces 2 moles of KCl and 3 moles of O₂. Therefore,

$$v(O_2) = \frac{3}{2} v(KCl) = 1.5 \times 0.4641 \ \text{mol} = 0.6962 \ \text{mol}$$

Thus, the mass of O₂ is:

$$m = v(O_2) \times Mr(O_2) = 0.6962 \ \text{mol} \times 32 \ \text{g mol}^{-1} = 22.28 \ \text{g}$$

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