The equilibrium constant Kp for the oxidation of sulphur dioxide into sulphur trioxide is 5.6x10⁴ at 350°C . if the partial pressure of SO2 and SO3 are 0.64 atm and 0.58 atm respectively, what is the partial pressure of O2 in the system?
2SO2+ O2-> 2SO3
Solution:
Balanced chemical equation:
2SO2 + O2 → 2SO3
The equilibrium constant expression for the reaction, Kp:
Kp = 5.6×104
PSO3 = 0.58 atm
PSO2 = 0.64 atm
PO2 = unknown
Therefore,
Answer: The partial pressure of O2 is 1.47×10−5 atm
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