Answer to Question #340936 in Chemistry for shimmy

Question

5.A balloon has a volume of 2.25 L when the temperature is 400C. What will be the volume if the balloon is cooled to 120C? Assume the pressure to be constant.

Answer 1

Given:

V₁ = 2.25 L

T₁ = 40°C + 273.15 = 313.15 K

P = constant

V₂ = unknown

T₂ = 12°C + 273.15 = 285.15 K

Formula: V₁/T₁ = V₂/T₂

Solution:

Since the pressure and amount of gas remain unchanged, Charles's law can be used.

Charles's law can be expressed as: V₁ / T₁ = V₂ / T₂

V₁T₂ = V₂T₁

To find the resulting volume of the balloon, solve the equation for V₂:

V₂ = V₁T₂ / T₁

V₂ = (2.25 L × 285.15 K) / (313.15 K) = 2.05 L

V₂ = 2.05 L

Answer: The volume of the balloon will be 2.05 L