Answer to Question #340931 in Chemistry for shimmy

Question

2. If 15.0 L Neon at 60 0C is heated at constant pressure, what temperature will it have if it occupies a volume of 4.50 L?

Given: V1= 15.0L V2 = 4.50 L T1 = 60 0C Convert 60 0C + 273 K = 333 K

Answer 1

Given:

V₁ = 15.0 L

T₁ = 60°C + 273 = 333 K

P₁ = P₂ = constant

V₂ = 4.50 L

T₂ = unknown

Formula: V₁/T₁ = V₂/T₂

Solution:

Since the pressure and amount of gas remain unchanged, Charles's law can be used.

Charles's law can be expressed as: V₁ / T₁ = V₂ / T₂

V₁T₂ = V₂T₁

To find the temperture, solve the equation for T₂:

T₂ = V₂T₁ / V₁

T₂ = (4.50 L × 333 K) / (15.0 L) = 99.9 K = 100 K

T₂ = 100 K or −173°C

Answer: at 100 K