Answer to Question #340930 in Chemistry for shimmy

Question

1. A hot air balloon has a volume of 2800 m3 at 990C. What is the volume if the air cools to 800C.

Given: V1 = 2800m3 T1=99°C+273K = 372 K T2 =80°C +273K =353K

Answer 1

Given:

V₁ = 2800 m³

T₁ = 99°C + 273.15 = 372.15 K

P₁ = P₂ = constant

V₂ = ???

T₂ = 80°C + 273.15 = 353.15 K

Formula: V₁ / T₁ = V₂ / T₂

Solution:

Since the pressure and amount of gas remain unchanged, Charles's law can be used.

Charles's law can be expressed as: V₁ / T₁ = V₂ / T₂

V₁T₂ = V₂T₁

To find the volume, solve the equation for V₂:

V₂ = V₁T₂ / T₁

V₂ = (2800 m³ × 353.15 K) / (372.15 K ) = 2657 m³

V₂ = 2657 m³

Answer: The volume is 2657 m³