Question

3. At 250C, the volume of chlorine gas is 15 dm3 .What is the resulting volume if the temperature is adjusted to 320K provided that the pressure remains constant?

Answer 1

Given:

V₁ = 15 dm³

T₁ = 25°C + 273 = 298 K

P₁ = P₂ = constant

V₂ = unknown

T₂ = 320 K

Formula: V₁/T₁ = V₂/T₂

Solution:

Since the pressure and amount of gas remain unchanged, Charles's law can be used.

Charles's law can be expressed as: V₁ / T₁ = V₂ / T₂

V₁T₂ = V₂T₁

To find the resulting volume, solve the equation for V₂:

V₂ = V₁T₂ / T₁

V₂ = (15 dm³ × 320 K) / (298 K) = 16.11 dm³

V₂ = 16.11 dm³

Answer: The resulting volume of chlorine gas is 16.11 dm³