How much time will be required for a sample of H-3 to lose 75% of its radioactivity? The half-life of tritium is 12.26 years.?
Solution:
Tritium = H-3
The half-life (t1/2) of tritium is 12.26 years.
From law of radioactive decay:
t1/2 = ln(2) / λ
where λ = decay constant
λ = ln(2) / t1/2
λ = (0.693) / (12.26 years) = 0.0565 years-1
Radioactive decay follows the kinetics of a first order reaction:
ln[H-3]t = -λt + ln[H-3]o
If the sample lose 75% (0.75), then 25% (0.25) remains.
[H-3]t = 0.25
[H-3]o = 1.00
λ = 0.0565 years-1
Therefore,
ln(0.25) = - (0.0565 years-1) × t + ln(1.00)
-1.3863 = - (0.0565 years-1) × t
t = (-1.3863) / (-0.0565) = 24.54 years
t = 24.54 years
Answer: 24.54 years will be required for a sample of H-3 to lose 75% of its radioactivity.
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