Substances A and B have retention times 8.20 and 8.815 min, respectively, on a 30.0 cm
column. An unretained species passes through the column in 1.30 min. The peak withs (at
base) foe A ana B are 0.555 and 0.605 min, respectively. Calculate:
a. The column resolution
b. The average number of theoretical plates in the column.
c. The plate height
d. The length of the column required to achieve a resolution of 1.5. Note that
Rs = βπ΅/π x (πΆ βπ/πΆ) x ( π²/π+ π²) and the quantities K and Ξ± do not change greatly with
increasing N and L. Substitute N1 and N2 in this equation and divide.
e. The time required to elute substance B on the column that Rs value of 1.5. Note that
π‘π =(ππ πΉ x πΊ/π x π―)/π x (πΆ/(πΆ β π ))squared
x ((π+π²)cubed/π² squared) and the quantities K and Ξ± do not change greatly
with increasing N and L. Substitute Rs1 and Rs2 in this equation and divide.
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