Answer to Question #274336 in Chemistry for Lizzy

Question

If it requires 75.0 mL of 0.500M NaOH to neutralize 165.0 mL of an HCI solution, what is the concentration of the HCI solution?

Answer 1

Solution:

Balanced chemical equation:

NaOH + HCl → NaCl + H₂O

According to stoichiometry:

n(NaOH) = n(HCl)

C_M(NaOH) × V(NaOH) = C_M(HCl) × V(HCl)

Therefore,

C_M(HCl) = C_M(NaOH) × V(NaOH) / V(HCl)

C_M(HCl) = (0.500 M × 75.0 mL) / (165.0 mL) = 0.227 M

C_M(HCl) = 0.227 M

Answer: The concentration of the HCI solution is 0.227 M