Using the following chemical equation how many grams of carbon dioxide can be produced by burning 18.49 g of butane?
C4H10 + 5O2 -> 3CO2 + 4H2O
According to the equation, equal numbers of moles of butane and carbon dioxide must be used and produced, respectively. From here:
m(CO2) = m(C4H10) × Mr(CO2) / Mr(C4H10) = 18.49 g × 44.01 g / 58.12 g = 12.76 g
Answer: 12.76 g
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