How many molecules are present in 500 milimole of AlCl3? How many atoms is this.
According to the Avogadro's number, one mole of any substance contains 6.022 × 10²³ particles. From here, 500 mmol of AlCl3 contains:
n(AlCl3) = 6.022 × 10²³ × 500 mmol = 6.022 × 10²³ × 0.5 mol = 3.011 × 10²³ molecules
As one molecule of AlCl3 consists off four atoms, the number of atoms is 500 mmol of AlCl3 is:
n(atoms) = 3.011 × 10²³ × 4 = 1.2044 × 10²⁴
Answer: 6.022 × 10²³ molecules; 1.2044 × 10²⁴ atoms
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