Answer to Question #162371 in Chemistry for Ava Brooke

Question

Using the following chemical equation how many liters of carbon dioxide can be produced by burning 79 L of oxygen?

C₄H₁₀ + 5O₂ -> 3CO₂ + 4H₂O

Answer 1

C₄H₁₀ + 5O₂ -> 3CO₂ + 4H₂O - unbalanced equation

Solution:

The balanced chemical equation:

2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O

According to the equation above: n(O₂)/13 = n(CO₂)/8

At STP, one mole of any gas occupies a volume of 22.4 L (V_m).

Hence,

V(O₂) / (13 × V_m) = V(CO₂) / (8 × V_m)

V(O₂) / 13 = V(CO₂) / 8

To find the volume of carbon dioxide, solve the equation for V(CO₂):

V(CO₂) = 8 × V(O₂) / 13 = 8 × 79 L / 13 = 48.615 L = 48.62 L

V(CO₂) = 48.62 L

Answer: 48.62 liters of carbon dioxide (CO₂) can be produced.

However, if an unbalanced equation is used, 47.4 liters of carbon dioxide (CO₂) can be produced.