Using the following chemical equation how many grams of water can be produced when 109 L of carbon dioxide are produced?
C4H10 + 5O2 -> 3CO2 + 4H2O
C4H10 + 5O2 -> 3CO2 + 4H2O
According to the equation, the mass of water equals:
m(H2O) = V(CO2) × 4 × Mr(H2O) / (3 × Vmol) = 109 L × 4 × 18 g/mol / (3 × 22.4 L) = 116.8 g
Answer: 116.8 g
Comments
Leave a comment