Answer to Question #162193 in Chemistry for Zamaria Baugh

Question

1. The total pressure of a 3 gas mixture is 1007 mmHg.  The partial pressure of one gas is 0.460 atm, the partial pressure of another is 400. mmHg.  What is the partial pressure of the last gas?

Answer 1

The total pressure of a mixture of gases equals the sum of the individual gas pressures:

P_total = P₁ + P₂ + P₃

where P_total - total pressure, P₁, P₂, P₃ - partial pressures.

From here:

P₃ = P_total - P₁ - P₂ = 1007 mmHg - 0.460 atm - 400 mmHg = 1007 mmHg - 349.6 mmHg - 400 mmHg = 257.4 mmHg

Answer: 257.4 mmHg