M(NaCl) = 23+35.5 = 58.5 g/mol
M(NaHCO3) = 23+1+12+16*3 = 84 g/mol
As NaCl and NaHCO3 have the same amount of Na, theoretical mass of NaCl will be:
m(NaCl, theor) = m(NaHCO3)/M(NaHCO3)*M(NaCl) = m(NaHCO3)/84*58.5 = m(NaHCO3)/1.436
Answer: m(NaHCO3)/1.436
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