Answer to Question #150403 in Organic Chemistry for Maria

Question

If I react 2.9(10)²⁰ molecules of C12H22O11 how many grams of COs will be made?
C12H22O11 + O2 --> CO2 + H2O

Answer 1

Solution:

The balanced chemical equation:

C₁₂H₂₂O₁₁ + 12O₂ --> 12CO₂ + 11H₂O

According to the equation: n(C₁₂H₂₂O₁₁) = n(CO₂) / 12

One mole of any substance contains 6.022×10²³ atoms/molecules.

Hence,

n(C₁₂H₂₂O₁₁) = (2.9×10²⁰ molecules / 6.022×10²³ molecules) × 1 mol = 0.00048 moles C₁₂H₂₂O₁₁

n(C₁₂H₂₂O₁₁) = n(CO₂) / 12

n(CO₂) = 12 × n(C₁₂H₂₂O₁₁) = 12 × 0.00048 moles = 0.00576 moles

Moles of CO₂ = n(CO₂) = Mass of CO₂ / Molar mass of CO₂

The molar mass of CO₂ is 44.01 g mol^-1.

Hence,

Mass of CO₂ = n(CO₂) × M(CO₂) = 0.00576 moles × 44.01 g mol^-1 = 0.2535 g

Mass of CO₂ is 0.2535 grams.

Answer: 0.2535 grams of CO₂ will be made.