Answer to Question #150393 in Organic Chemistry for Maria

Question

How many molecules of Ag2So4 will be made if 2.7 grams of AgNO3 are reacted?
AgNO3 + H2SO4 --> Ag2SO4 + HNO3

Answer 1

Solution:

The balanced chemical equation:

2AgNO₃ + H₂SO₄ --> Ag₂SO₄ + 2HNO₃

According to the equation: n(AgNO₃) / 2 = n(Ag₂SO₄)

Moles of AgNO₃ = n(AgNO₃) = Mass of AgNO₃ / Molar mass of AgNO₃

The molar mass of AgNO₃ is 169.87 g/mol.

Hence,

n(AgNO₃) = 2.7 g / 169.87 g mol^-1 = 0.01589 moles

n(Ag₂SO₄) = n(AgNO₃) / 2 = 0.01589 moles / 2 = 0.007945 moles

One mole of any substance contains 6.022×10²³ atoms/molecules.

Hence,

Number of Ag₂SO₄ molecules = (0.007945 mol) × (6.022×10²³ molecules / 1 mol) = 4.78×10²¹ molecule

Number of Ag₂SO₄ molecules = 4.78×10²¹ molecules

Answer: 4.78×10²¹ molecules of Ag₂SO₄ will be made.

The final calculation formula considering all steps:

2.7 g AgNO₃ × (1 mol AgNO₃ / 169.87 g AgNO₃) × (1 mol Ag₂SO₄ / 2 mol AgNO₃) × (6.022×10²³ molecules Ag₂SO₄ / 1 mol Ag₂SO₄) = 4.78×10²¹ molecules Ag₂SO₄