The balanced equation for the reaction above is;
"2AgNO_3 + H_2SO_4 \\to Ag_2SO_4 + 2HNO_3"
mass of AgNO3 = 2.7g
number of moles of AgNO3 = 2.7/169.87 = 0.016 moles
From the reaction above, 2 moles of AgNO3 will react to produce 1 mole of Ag2SO4
0.016 moles of AgNO3 will therefore produce 0.008 moles of Ag2SO4
0.008 moles = 0.008 × 6.02×10²³ = 4.82×10²¹ molecules
This means that 4.82×10²¹ molecules of Ag2SO4 would be made in the reaction.
Comments
Leave a comment