The null hypothesis adopted is that there is,
“there is no
difference in their reliability”.
•
Assuming that the workers use the laboratory for an
equal length of time, we would expect, from the null
hypothesis, the same number of breakages by each
worker.
•
Since the total number of breakages is 61, the expected
number of breakages per worker is 61/4 = 15.25.
It’s not possible in practice to have a non-integral
number of breakages.
•
The nearest practicable ‘equal’ distributions would be15,
15, 15, 16.
•
The question to be answered is whether the difference
between the observed and expected frequencies is so
large that the null hypothesis should be rejected.
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