Answer to Question #97222 in General Chemistry for Jaylee Rencountre

General Chemistry

Question #97222

How many carbon atoms are there in 10.0 kilograms of sucrose C12H22O11?

Expert's answer

n=m/M=N/N_aM=12*12+1*22+16*11=342 g/mol

10 kg = 10000g

n= 10000/342=29.24 mol

N(C12H22O11)=29.24*6.02*10^23=1.76*10^25 molec.

N(C)=1.76*10^25 * 12 = 2.11*10^26 atoms

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